22x^2=840

Solution for 22x^2=840 equation:

22x^2=840

We move all terms to the left:

22x^2-(840)=0

a = 22; b = 0; c = -840;
Δ = b2-4ac
Δ = 02-4·22·(-840)
Δ = 73920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{73920}=\sqrt{64*1155}=\sqrt{64}*\sqrt{1155}=8\sqrt{1155}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{1155}}{2*22}=\frac{0-8\sqrt{1155}}{44}
=-\frac{8\sqrt{1155}}{44}
=-\frac{2\sqrt{1155}}{11}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{1155}}{2*22}=\frac{0+8\sqrt{1155}}{44}
=\frac{8\sqrt{1155}}{44}
=\frac{2\sqrt{1155}}{11}
$